Emmett Thompson asked:
"Why did GM take the glow plug power off the voltage dropping resistor? Why
not just take 12 vdc off the normal vehicle wiring?"
Well, Let me get out my "wash and wear" answer for this as I have written
many articles on this very subject and about 3 weeks later it is asked
again!
GM didn't take the wire off of the resistor, it is an "in shop" modification
that enhances starting the vehicle through stability of the 12 volts to the
glowplug network. The resistor is to drop the 24 volts to 12 volts to the
glow plugs. The glow plugs use 12 Volts and 24 would be too much across
them. Now, here is why the resistor is used: All M series vehicles use a
NATO slave plug to jump/slave another vehicle. If the batteries are stone
dead in a CUCV, 24 volts will still feed the glow plug circuit and it will
start when slaved in its' original unmodified condition. However, this
should be noted that through the modification the vehicle will start easier
BUT if your CUCV batteries are stone dead when slaved, you will NOT get 12
volts to the glow plug circuit because the dead batteries will drop the
entire 24 volts to the center of the two batteries until they charge. This
must be kept in mind when jumping off the vehicle with the modification as
it will not start through the slave recepticle until the batteries charge up
to some degree. The modification is to remove the red wire from the
output of the glowbar resistor and connect it directly to the 12 volt buss
directly above the glowplug relay. The terminal fits perfectly and the wire
is the right length which makes a nice job. I hope this answers this
question again. Your jeep nut, Julian Burke
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