The RPM rating of the torque value is the same RPM for its equivalent HP.
This is not a formula to determine the peak torque and peak HP of an engine.
There is no such thing. HP is a value calculated from torque at a given RPM.
It is not measurable by itself.
These articles discuss how James Watt came up with the formula to relate his
steam engines' output to the work of the horses it replaced:
http://www.offroaders.com/info/tech-corner/reading/horsepower-torque.htm
http://www.eidnet.org/local/westers_garage/horsepower.htm
Therefore, for the 138 lb-ft rating @ 2000 RPM would equate to 52.55 HP @
2000 RPM. The 80 HP rating is at 3750 RPM. The torque at 3750 RPM would be
approximately 112 lb-ft.
Whether or not you are talking about Corvettes or MV's, the formula is
relevant and it is constant.
Hope this clears up some confusion.
>This doesn't seem to work and how does it refer to engines that don't even
>make 5252 rpm without exploding ?
>
>eg, looking at RR Manual TSD 702 for the B Range engine we have:
>the B 40, 80 BHP @ 3750rpm and 138 lb.ft @ 2000 rpm, using the equation it
>gives a BHP answer of 52.55.
>
>The B 60 (for all you Ferret owners) is 130 BHP @ 3750 rpm and 209 lb.ft @
>2400 rpm which gives 95.51 HP.
>
>For the B 81 we have 235 HP @ 4000rpm and 354 lb. ft @ 2500rpm giving
>168.51HP
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